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392    Chapter 11    Analyzing Genomic Variation




                             WHAT’S NEXT

              In this chapter and in Chapters 9 and 10, we have focused   different types of proteins that help package and manage the
              on the nucleotide content of genomes, particularly the   information carried by DNA. These proteins have many
              6  billion  nucleotides  organized  into 46 chromosomes in   roles. Certain proteins help compact the chromosomes to fit
              each normal human diploid cell. In the next several chap-  in the nucleus. Some proteins ensure that the chromosomal
              ters, we examine features of the chromosomes that allow   DNA is properly duplicated during each cell cycle, while
              these DNA sequences to function properly and to be trans-  others govern the distribution of chromosomes to daughter
              mitted from one generation to the next.              cells. Yet other proteins are responsible for regulating the
                  We begin by considering how in spite of the enormous   availability of genes to the transcriptional machinery so that
              complexity of DNA sequences, the DNA actually constitutes   the genes can be expressed into proteins. In Chapter 12, we
              only about one-third of the total mass of a chromosome. The   examine how proteins interact with DNA to generate the
              remainder of the chromosome is made of thousands of   functional complexity of a chromosome.



                             SOLVED PROBLEMS

                I.  Genomic DNA from a woman’s blood cells is PCR   maternally derived chromosome and one on the paternally
                  amplified by a single pair of primers representing a   derived chromosome), as long as the primer can hybridize to
                  unique locus in the genome. The PCR products are   both homologs as is usually the case. The DNA sequence
                  then sequenced by the Sanger method, using one of the   trace has two nucleotides at several positions. This fact indi-
                  PCR primers as a sequencing primer. The following   cates that the woman must be a heterozygote and that the
                  figure shows a trace of just part of the sequence read.  PCR is amplifying both alleles of the locus.
                                                                    a.  Notice that both alleles contain multiple repeats of
                                G    T     A    C
                                                                       the dinucleotide CA. The most likely explanation
                                                                       for the polymorphism is therefore that the locus
                                                                       contains an SSR polymorphism whose alleles have
                                                                       different numbers of CA repeats. One allele has
                                                                       six repeats; the second allele must have more
                                                                       CA units.

                       Smaller                       Larger         b. Writing out the first 14 nucleotides of both alleles is
                                                                       straightforward. If the assumption in part (a) is cor-
               a.  What kind of polymorphism is most likely represented?  rect, then one allele should have more than six CA
               b. With your answer to part (a) in mind, determine the   repeats. The trace shows evidence for two additional
                  woman’s genotype at this locus. Indicate all nucleo-  CA repeats in one allele at positions 15–18, for a to-
                  tides that can be read from both alleles and their    tal of eight CA repeats. 
                  5′-to-3′ orientation.                                   You can then determine the nucleotides beyond
               c.  What kind of molecular event was likely to have gen-  the repeats in the shorter allele by subtracting CACA
                  erated this polymorphism?                            from positions 15–18. The remaining peaks at these
               d. How would you know exactly where in the genome       positions correspond to ATGT. Note that ATGT can
                  this locus is found?                                 also be found in the longer allele, but now at nucleo-
               e.  What is another way in which you could analyze the   tides 19–22, just past the two additional CACA re-
                  PCR products to genotype this locus?                 peats. You can determine the last four nucleotides in
               f.  Suppose you wanted to genotype this locus based on   the shorter allele by subtracting ATGT from positions
                  single-molecule DNA sequencing of whole genomes      19–22, revealing TAGG. The sequences of the two
                  as shown in Fig. 9.24. Would a single read suffice for   alleles of this SSR locus (indicating only one strand
                  genotyping the locus by this alternative method?     of DNA each) are thus:
                                                                           Allele 1: 5′...GGCACACACACACAATGTTAGG...3′
              Answer                                                       Allele 2: 5′...GGCACACACACACACACAATGT...3′
              To solve this problem, you need to understand that PCR will   c.  The mechanism thought to be responsible for most
              simultaneously amplify both copies of a locus (one on the   SSR polymorphisms is stuttering of DNA polymerase
              DNA: © Design Pics/Bilderbuch RF                         during DNA replication.
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