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Solved Problems   77


                                                                             •  A continuous trait can have any value of expression
                        essential concepts
                                                                               between two extremes. Most traits of this type are
                                                                               polygenic, that is, determined by the interactions of
                         •  In incomplete penetrance, a phenotype is expressed in
                          fewer than 100% of individuals having the same       multiple genes.
                          genotype. In variable expressivity, a phenotype is   •  The environment and random events can interact with
                          expressed at different levels among individuals with the   genes to influence the expression of many so-called
                          same genotype.                                       multifactorial traits.




                                      WHAT’S NEXT


                       Part of Mendel’s genius was to look at the genetic basis of   this chapter. Each embellishment extends the range of
                       variation through a very narrow window, focusing his first   Mendelian analysis and deepens our understanding of the
                       glimpse of the mechanisms of inheritance on simple yet   genetic basis of variation. And no matter how broad the
                       fundamental phenomena. Mendel worked on just a handful   view, Mendel’s basic conclusions, embodied in his first law
                       of traits in inbred populations of one species. For each trait,   of segregation, remain valid.
                       he manipulated one gene with one completely dominant    But what about Mendel’s second law that genes assort
                       and one recessive allele that determined two distinguish-  independently?  As  it  turns  out,  its  application  is  not  as
                       able, or discontinuous, phenotypes. Both the dominant and   universal as that of the law of segregation. Many genes do
                       recessive alleles showed complete penetrance and negligi-  assort independently, but some do not; rather, the two
                       ble differences in expressivity.                    genes appear to be linked and transmitted together from
                          In the first few decades of the twentieth century, many   generation to generation. An understanding of this fact
                       biologists questioned the general applicability of Mende-  emerged from studies that located Mendel’s hereditary
                       lian analysis, for it seemed to shed little light on the com-  units, the genes, in specific cellular organelles, the chro-
                       plex inheritance patterns of most plant and animal traits or   mosomes. In describing how researchers deduced that
                       on the mechanisms producing continuous variation. Simple   genes travel with chromosomes, Chapter 4 establishes the
                       embellishments, however, clarified the genetic basis of   physical basis of inheritance, including the segregation of
                       continuous variation and provided explanations for other   alleles, and clarifies why some genes assort independently
                       apparent exceptions to Mendelian analysis as described in   while others do not.


                                      SOLVED PROBLEMS


                         I.  Imagine you purchased an albino mouse (genotype   informative.) What alleles of the  B gene should the test
                          cc) in a pet store. The c allele is epistatic to other coat   mouse carry? To make this decision, work through the ex-
                          color genes. How would you go about determining   pected results using each of the possible genotypes.
                          the genotype of this mouse at the brown locus? (In
                          pigmented mice, BB and Bb are black, bb is brown.)  Test mouse           Albino     Expected non-
                                                                             genotype              mouse      albino progeny
                       Answer                                                BB            ×        BB        all black
                                                                                           ×        Bb        all black
                       This problem requires an understanding of gene interactions,        ×        bb        all black
                       specifically epistasis. You have been placed in the role of   Bb    ×        BB        all black
                       experimenter and need to design crosses that will answer the        ×        Bb        3/4 black, 1/4 brown
                       question. To determine the alleles of the B gene present, you       ×        bb        1/2 black, 1/2 brown
                       need to eliminate the blocking action of the cc genotype.   bb      ×        BB        all black
                                                                                                              1/2 black, 1/2 brown
                                                                                           ×
                                                                                                    Bb
                       Because only the recessive c allele is epistatic, when a C al-      ×        bb        all brown
                       lele is present, no epistasis will occur. To introduce a C allele
                       during the mating, the test mouse you mate to your albino   From these hypothetical crosses, you can see that a test
                       can have the genotype CC or Cc. (If the mouse is Cc, half    mouse with either the  Bb or  bb genotype would yield
                       the progeny will be albino and will not contribute useful in-    distinct outcomes for each of the three possible albino
                       formation, but the non-albinos from this cross would be   mouse genotypes. However, a bb test mouse would be more
                       DNA: © Design Pics/Bilderbuch RF
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