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172    Chapter 5    Linkage, Recombination, and the Mapping of Genes on Chromosomes


                  Assume for the moment that the same is true in hu-   a.  Are the a and w loci linked? If so, how far apart
                  mans. The disease sickle-cell anemia is the result of   are they?
                  homozygosity for a particular mutation in the        b. What was the genotype of the blue smooth parent?
                  β-globin gene.                                         Include the chromosome arrangement of alleles.
                  a.  A son is born to an albino man and a woman with   c.  If a plant grown from a blue wrinkled progeny seed
                    sickle-cell anemia. What kinds of gametes will the   is crossed to a plant grown from a yellow smooth
                    son form, and in what proportions?                   F 1  seed, what kinds of kernels would be expected,
                  b. A daughter is born to a normal man and a woman      and in what proportions?
                    who has both albinism and sickle-cell anemia.     13.  If the a and b loci are 40 cM apart and an AA BB indi-
                    What kinds of gametes will the daughter form,      vidual and an aa bb individual mate:
                    and in what proportions?                           a.  What gametes will the F 1  individuals produce, and
                  c.  If the son in part (a) grows up and marries the    in what proportions? What phenotypic classes in
                    daughter in part (b), what is the probability that a   what proportions are expected in the F 2  generation
                    child of theirs will be an albino with sickle-cell   (assuming complete dominance for both genes)?
                    anemia?                                            b. If the original cross was AA bb × aa BB, what
                10.  In a particular human family, John and his mother     gametic proportions would emerge from the F 1 ?
                  both have brachydactyly (a rare autosomal domi-        What would be the result in the F 2  generation?
                  nant allele causing short fingers). John’s father has     14.  Write the number of different kinds of phenotypes,
                  Huntington disease (another rare autosomal domi-     excluding sex, you would see among a large number
                  nant allele). John’s wife is phenotypically normal   of progeny from an F 1  mating between individuals of
                  and is pregnant. Two-thirds of people who inherit    identical genotype that are heterozygous for one or
                  the Huntington (HD) allele show symptoms by age      two genes (that is, Aa or Aa Bb) as indicated. No gene
                  50, and John is 50 and has no symptoms.              interactions means that the phenotype determined by
                  Brachydactyly is 90% penetrant.                      one gene is not influenced by the genotype of the
                  a.  What are the genotypes of John’s parents?        other gene.
                  b. What are the possible genotypes for John? How     a.  One gene; A completely dominant to a.
                    likely is John to have each of these genotypes?    b. One gene; A and a codominant.
                  c.  What is the probability the child will express both
                    brachydactyly and Huntington disease by age 50 if   c.  One gene; A incompletely dominant to a.
                    the two genes are unlinked?                        d. Two unlinked genes; no gene interactions; A
                  d. How will your answer to part (c) change if instead   completely dominant to a, and B completely
                    these two loci are 20 m.u. apart?                    dominant to b.
                11.  Albino rabbits (lacking pigment) are homozygous for   e.  Two genes, 10 m.u. apart; no gene interactions; A
                                                                         completely dominant to a, and B completely domi-
                  the recessive c allele (C allows pigment formation).
                  Rabbits homozygous for the recessive b allele make     nant to b.
                  brown pigment, while those with at least one copy of   f.  Two unlinked genes; no gene interactions; A and
                  B make black pigment. True-breeding brown rabbits      a codominant, and B incompletely dominant to b.
                  were crossed to albinos, which were also BB. F 1  rab-  g. Two genes, 10 m.u. apart; A completely dominant
                  bits, which were all black, were crossed to the double   to a, and B completely dominant to b; and with
                  recessive (bb cc). The progeny obtained were 34        recessive epistasis between aa and the alleles of
                  black, 66 brown, and 100 albino.                       gene B.
                  a.  What phenotypic proportions would have been      h. Two unlinked duplicated genes (that is, A and B
                    expected if the b and c loci were unlinked?          perform the same function); A and B completely
                  b. How far apart are the two loci?                     dominant to a and b, respectively.
                12.  In corn, the allele A allows the deposition of anthocy-  i.  Two genes, 0 m.u. apart; no gene interactions; A
                  anin (blue) pigment in the kernels (seeds), while aa   completely dominant to a, and B completely domi-
                  plants have yellow kernels. At a second gene, W–       nant to b. (Two possible answers exist.)
                  produces smooth kernels, while ww kernels are wrin-    15.  A DNA variant has been found linked to a rare auto-
                  kled. A plant with blue smooth kernels was crossed   somal dominant disease in humans and can thus be
                  to a plant with yellow wrinkled kernels. The progeny   used as a marker to follow inheritance of the disease
                  consisted of 1447 blue smooth, 169 blue wrinkled,    allele. In an informative family (in which one parent
                  186 yellow smooth, and 1510 yellow wrinkled.         is heterozygous for both the disease allele and the
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